A subnet on IPv6 is always /64, regardless if you get IN ADDITION a prefix.
The example with IP assign /60 issues the router request a /60 to use for further sub delegations. But then again each network on a link is a /64, only exception would be point to point links.
Well that's what I meant?
Yeah the network itself (devices on it) will be /64
The example with IP assign /60 issues the router request a /60 to use for further sub delegations.
Yep, I think that 's what @mk24 was thinking about. Somehow tell ISP's router that LAN has /57 available for delegation. Probably I just use bad vocabulary.
EDIT: Another example: I suspect that in OpenWrt when you create static protocol interface and set the static IPv6 to say 2001:db8::1/60 means: this network is 2001:db8::1/64 but you can delegate /60. This is IMO more of about interpretation of something you can put in some text input in WebUI.
Layer-2 is the link; and on Layer-3 we have the network. In IPv4 we have as a legacy speak this kind of "network" and "subnet" because before CIDR there was only /8, /16, and /24.
On IPv6 a subnet (or network, depends who you ask) has to be /64; again, the only exception are point-to-point link, without SLAAC then!
To maybe confuse you even more: A network could also be the whole network on an organization. Like with IPv4 a /20, or with IPv6 a /32.
I finally got it working. My ISP is absolutely horrible. So first they tell me no bridge mode on their ONT. Then they wont help me because I am not using their router. So I dig through my stuff, find their router but not the power supply. I ended up using my lab power supply and made a power cable. Get their stuff all hooked back up and call them back. Guess what after about an hour of troubleshooting the rep tells me their ONT needs to be in bridge mode! As soon as bridge mode was enabled everything worked!
Thank you to everyone that helped. Your assistance was greatly appreciated.
So they turned on bridge mode remotely for you?
wrt support: with many companies it's hard to get to anybody competent
mandatory xkcd 806