Filtering values from Json format without jq

[thinkopensource]

Hi
Im checking inside a openwrt to see If is possible to filter json string to have the values.

For example {"address":"192.168.2.2","user":"user1","groups":"permissions"}

I receive from curl the string and I need to separate values to pass vars to other commands.

For now Im checking some examples but not works

#!/bin/sh
. /usr/share/libubox/jshn.sh 
json_init
json_load '$(cat $STRING)'
json_get_keys keys
for k in $keys; do 
   json_get_var v "$k"
   echo "$k : $v"
done

But produce error "Failed to parse message data"

My problem is justly that I can't use jq, or python to choose data, so I think the solution is to separate first and send to vars every value, making something usable. I was checking jshn and jsonfilter utilities but for this type of json not seems to work.

Suggestions?

[fantom-x]

@thinkopensource

Suggestions?

Google something like "bash split json" and you will find tons of examples on how to do that.

[thinkopensource]

Hi

For now I detected first error

json_load '$(cat $RESPONSE)' needs to be

json_load $(echo $RESPONSE)

[jow]

You can use OpenWrt’s builtin jsonfilter command.

eval $(jsonfilter -s '{"address":"192.168.2.2","user":"user1","groups":"permissions"}' -e 'ADDRESS=@.address' -e 'USER=@.user')
echo "address=$ADDRESS user=$USER"

[thinkopensource]

Great!!

I prefer this option to filter, but I never found the form to use -e option.

Thanks