Cc1: note: someone does not honour COPTS correctly, passed 0 times

Hi All,
on OpenWrt 19.07 i try to compile my custom package and i get a lot of "cc1: note: someone does not honour COPTS correctly, passed 0 times" , i think is -fhonour-copts default compiler option related.

What is the real meaning of this note ? is it really -fhonour-copts related ? how can avoid it ?

the following is package Makefile build/compile parts

define Build/Compile
        $(MAKE) -C $(PKG_BUILD_DIR)/src \
               CC="$(TARGET_CC)" \
           CFLAGS="$(TARGET_CFLAGS)" \
          LDFLAGS="$(TARGET_LDFLAGS)"
endef

and my application Makefile do not append any CFLAGS

CFLAGS =  
CPPFLAGS = 

# Rule for compiling (always first)
%.o: %.c
	$(CC) $(CFLAGS) $< -c -o $@

# Rule for building dependencies from source (always second)
%.d: %.c
	$(CC) -M $(CFLAGS) $< > $@

Any support will be appreciated.
Thanks in advance
B/R

Hi All,
on OpenWrt 19.07 i try to compile my custom package and i get a lot of "cc1: note: someone does not honour COPTS correctly, passed 0 times" , i think is -fhonour-copts default compiler option related.

What is the real meaning of this note ? is it really -fhonour-copts related ? how can avoid it ?

the following is package Makefile build/compile parts

define Build/Compile
        $(MAKE) -C $(PKG_BUILD_DIR)/src \
               CC="$(TARGET_CC)" \
           CFLAGS="$(TARGET_CFLAGS)" \
          LDFLAGS="$(TARGET_LDFLAGS)"
endef

and my application Makefile do not append any CFLAGS

CFLAGS =  
CPPFLAGS = 

# Rule for compiling (always first)
%.o: %.c
	$(CC) $(CFLAGS) $< -c -o $@

# Rule for building dependencies from source (always second)
%.d: %.c
	$(CC) -M $(CFLAGS) $< > $@

Any support will be appreciated.
Thanks in advance
B/R